DNA Polymerase I Large (Klenow) Fragment
Klenow Fragment、DNA Polymerase I Large (Klenow) Fragment
- 价格: ¥550
- 规格:
- 数量:

产品介绍
- 产品介绍
- 操作详情
产品组分
Storage Solution: 5 U/ul Klenow Fragment、25 mM Tris-HCl, 1 mM DTT, 0.1 mM EDTA, 50% Glycerol, pH 7.4 @ 25°C 10*Reaction Buffer: 50 mM NaCl, 10 mM Tris-HCl, 10 mM MgCl2, 1 mM DTT (pH 7.9 @ 25°C)
操作步骤
1. DNA should be dissolved in 1*Reaction Buffer or T4 DNA Ligase Reaction buffer and supplemented with 33 μM each dNTP.
2. Add 1 unit of DNA Polymerase I Large (Klenow) Fragment per microgram DNA.
3. Incubate for 15 minutes at 25°C.
4. Stop reaction by adding EDTA to a final concentration of 10 mM and heating for 20 minutes at 75°C.
注意事项
1. Due to the 3´→5´ exonuclease activity of the enzyme, increasing the reaction temperature, adding too much enzyme, not adding dNTP or too long reaction time will lead to the formation of the dented end.
2. Please avoid repeated freeze-thaw cycles
- 产品数据
生物活性
The experiment was designed to synthesize two complementary DNA Oligos. Small DNA fragments with 5 'sticky ends were synthesized by annealing, and the sticky ends were completed by Klenow fragment to form flat ends. 20% Native PAGE glue (which can distinguish the size of 0.1 ~ 100bp) was used for electrophoresis, and the enzyme activity was verified. As can be seen from the result, the dsDNA fragment at the sticky end is mended by Klenow fragment, which has a larger molecular weight, and the electrophoretic band position is above the DNA fragment with the sticky end. The results show that UA070056-Klenow fragment has the same effect as a competing product N.
Lane 1 Negative Control
Lane 2 competing product N 0.44μg
Lane 3 competing product N 0.22μg
Lane 4 UA070056-Klenow fragment 0.44μg
Lane 5 UA070056-Klenow fragment 0.22μg
Lane 6 UA070056-Klenow fragment 0.42μg
Lane 7 UA070056-Klenow fragment 0.21μg
电泳(SDS-PAGE)
1μg (R: reducing condition, N: non-reducing condition).
反相高效液相色谱(RP-HPLC)
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